Each Of The Interior Angles Of A Regular Polygon Is 140°. Calculate The Sum Of All The Interior Angles Of The Polygon. - Each Of The Interior Angles Of A Regular Polygon Is 140 ...

Agustus 30, 2021

Each Of The Interior Angles Of A Regular Polygon Is 140°. Calculate The Sum Of All The Interior Angles Of The Polygon. - Each Of The Interior Angles Of A Regular Polygon Is 140 ... - We can tackle this problem in two ways.

Each Of The Interior Angles Of A Regular Polygon Is 140°. Calculate The Sum Of All The Interior Angles Of The Polygon. - Each Of The Interior Angles Of A Regular Polygon Is 140 ... - We can tackle this problem in two ways.. We can tackle this problem in two ways. (b) sum of exterior angles of a polygon = 360o (c) each exterior angle of a regular n sided polygon (e)= n 3600 (d) regular pentagon oeach exterior angle = 72 oeach interior angle = 108 (e) regular hexagon 2 2 2 2 each exterior angle = 60o each interior angle = 120o (f) regular octagon each exterior angle = 45o each interior angle o= 135 4. Since the interior angle 140 degrees, the supplement of this is the exterior angle and equal to 40 degrees. Hence the number of sides is 360/40 = 9 sides.

Since the interior angle 140 degrees, the supplement of this is the exterior angle and equal to 40 degrees. Hence the number of sides is 360/40 = 9 sides. We can tackle this problem in two ways. (b) sum of exterior angles of a polygon = 360o (c) each exterior angle of a regular n sided polygon (e)= n 3600 (d) regular pentagon oeach exterior angle = 72 oeach interior angle = 108 (e) regular hexagon 2 2 2 2 each exterior angle = 60o each interior angle = 120o (f) regular octagon each exterior angle = 45o each interior angle o= 135 4.

We can tackle this problem in two ways. (b) sum of exterior angles of a polygon = 360o (c) each exterior angle of a regular n sided polygon (e)= n 3600 (d) regular pentagon oeach exterior angle = 72 oeach interior angle = 108 (e) regular hexagon 2 2 2 2 each exterior angle = 60o each interior angle = 120o (f) regular octagon each exterior angle = 45o each interior angle o= 135 4. Since the interior angle 140 degrees, the supplement of this is the exterior angle and equal to 40 degrees. Hence the number of sides is 360/40 = 9 sides.

Since the interior angle 140 degrees, the supplement of this is the exterior angle and equal to 40 degrees.

(b) sum of exterior angles of a polygon = 360o (c) each exterior angle of a regular n sided polygon (e)= n 3600 (d) regular pentagon oeach exterior angle = 72 oeach interior angle = 108 (e) regular hexagon 2 2 2 2 each exterior angle = 60o each interior angle = 120o (f) regular octagon each exterior angle = 45o each interior angle o= 135 4. Hence the number of sides is 360/40 = 9 sides. Since the interior angle 140 degrees, the supplement of this is the exterior angle and equal to 40 degrees. We can tackle this problem in two ways.

Since the interior angle 140 degrees, the supplement of this is the exterior angle and equal to 40 degrees. Hence the number of sides is 360/40 = 9 sides. (b) sum of exterior angles of a polygon = 360o (c) each exterior angle of a regular n sided polygon (e)= n 3600 (d) regular pentagon oeach exterior angle = 72 oeach interior angle = 108 (e) regular hexagon 2 2 2 2 each exterior angle = 60o each interior angle = 120o (f) regular octagon each exterior angle = 45o each interior angle o= 135 4. We can tackle this problem in two ways.

We can tackle this problem in two ways. Since the interior angle 140 degrees, the supplement of this is the exterior angle and equal to 40 degrees. (b) sum of exterior angles of a polygon = 360o (c) each exterior angle of a regular n sided polygon (e)= n 3600 (d) regular pentagon oeach exterior angle = 72 oeach interior angle = 108 (e) regular hexagon 2 2 2 2 each exterior angle = 60o each interior angle = 120o (f) regular octagon each exterior angle = 45o each interior angle o= 135 4. Hence the number of sides is 360/40 = 9 sides.

(b) sum of exterior angles of a polygon = 360o (c) each exterior angle of a regular n sided polygon (e)= n 3600 (d) regular pentagon oeach exterior angle = 72 oeach interior angle = 108 (e) regular hexagon 2 2 2 2 each exterior angle = 60o each interior angle = 120o (f) regular octagon each exterior angle = 45o each interior angle o= 135 4.

(b) sum of exterior angles of a polygon = 360o (c) each exterior angle of a regular n sided polygon (e)= n 3600 (d) regular pentagon oeach exterior angle = 72 oeach interior angle = 108 (e) regular hexagon 2 2 2 2 each exterior angle = 60o each interior angle = 120o (f) regular octagon each exterior angle = 45o each interior angle o= 135 4. We can tackle this problem in two ways. Hence the number of sides is 360/40 = 9 sides. Since the interior angle 140 degrees, the supplement of this is the exterior angle and equal to 40 degrees.